POJ之路4--1004Financial Management

一、

Input

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

Output

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

很简单的一个题目，不过中间对于一个优先级问题困扰了好久，一步步尝试才找到问题。

temp=((int)(m*100))/100.0+((int)temp/5)*0.01;

temp=((int)m*100)/100.0+((int)temp/5)*0.01;

这两句代码，唯一的区别在于m*100是否加括号，但结果却不同，看来以前对于强制转换的认识有偏差。

比如=1.12，执行(int)(m*100) 得到112，而执行(int)m*100得到100。

最终AC的代码如下：

#include<iostream>
using namespace std;

int main()
{
	double money=0;
	float m;
	for(int i=0;i<12;i++)
	{
		cin>>m;
		money+=m;
	}
	m=money/12;
	float temp=(int)(m*1000)%10;
	temp=((int)(m*100))/100.0+((int)temp/5)*0.01;
	cout<<"$"<<temp;

	return 0;
}