Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
代码如下:
class Solution {
public:
int majorityElement(vector<int>& nums) {
size=1
if(nums.size()==1)
return nums[0];
size>1
sort(nums.begin(),nums.end());
int number = 1;
for(int i=1; i<nums.size(); i++)
{
if(nums[i]==nums[i-1])
{
number++;
if(number>=(nums.size()+1)/2)
return nums[i];
}
else
number = 1;
}
return 0;
}
};