Problem Description
Everybody knows any number can be combined by the prime number.
Now, your task is telling me what position of the largest prime factor.
The position of prime 2 is 1, prime 3 is 2, and prime 5 is 3, etc.
Specially, LPF(1) = 0.
Now, your task is telling me what position of the largest prime factor.
The position of prime 2 is 1, prime 3 is 2, and prime 5 is 3, etc.
Specially, LPF(1) = 0.
Input
Each line will contain one integer n(0 < n < 1000000).
Output
Output the LPF(n).
Sample Input
1 2 3 4 5
Sample Output
0 1 2 1 3
方法 :
素数筛选法。
代码:
#include
#define N 1000000
int p[N];
int main()
{
int i, j, n, k;
k = 1;
p[1] = 0;
for(i = 2; i < N; i++){
if(p[i] == 0){
for(j = i; j < N; j += i){
p[j] = k;
}
k++;
}
}
while(scanf("%d", &n) != EOF){
printf("%d\n", p[n]);
}
return 0;
}
本文介绍了一种通过素数筛选法找到任意整数的最大质因数位置的方法,并提供了具体的C语言实现代码。
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