Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3
, return true
.
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target)
{
if(matrix.size() == 0)
{
return false;
}
int i = 0;
int j = matrix[0].size() - 1;
while(1)
{
if(matrix[i][j] == target)
{
return true;
}
if(matrix[i][j] > target)
{
-- j;
}else
{
++ i;
}
if(i >= matrix.size() || j < 0)
{
return false;
}
}
return false;
}
};