算数表达式求值

不带括号时，直接遍历一次，再累和

#include <stdio.h>
#include <string.h>

int main(){
	char ch;
	int a[200], temp;
	while(scanf("%d", &a[0]) != EOF){
		int i = 0;
		while(scanf("%c", &ch) != EOF && ch != '\n'){
			scanf("%d", &temp);
			if(ch == '+') a[++i] = temp;
			else if(ch == '-') a[++i] = -temp;
			else if(ch == '*') a[i] *= temp;
			else if(ch == '/') a[i] /= temp;
		}
		for(int j = 1; j <= i; ++j)
			a[0] += a[j];
		printf("%d\n", a[0]);
	}
	return 0;
}