简单密码

他是这么变换的，大家都知道手机上的字母： 1--1， abc--2, def--3, ghi--4, jkl--5, mno--6, pqrs--7, tuv--8 wxyz--9, 0--0,就这么简单，渊子把密码中出现的小写字母都变成对应的数字，数字和其他的符号都不做变换，

 

声明：密码中没有空格，而密码中出现的大写字母则变成小写之后往后移一位，如：X，先变成小写，再往后移一位，不就是y了嘛，简单吧。记住，z往后移是a哦。

输入描述:

输入包括多个测试数据。输入是一个明文，密码长度不超过100个字符，输入直到文件结尾

输出描述:

输出渊子真正的密文

输入例子:

YUANzhi1987

输出例子:

zvbo9441987

#include<iostream>

using namespace std;

 

intmain()

{

    charstr[1001];

     

    while(cin.getline(str,1000)!=NULL)

    {

        inti = 0;

        while(str[i]!='\0')

        {

              if(str[i] >= 'a'&&str[i] <= 'c')

              {

                    str[i] = '2';

              }elseif(str[i] >= 'd'&&str[i] <= 'f')

              {

                    str[i] = '3';

              }elseif(str[i] >= 'g'&&str[i] <= 'i')

              {

                    str[i] = '4';

              }elseif(str[i] >= 'j'&&str[i] <= 'l')

              {

                    str[i] = '5';

              }elseif(str[i] >= 'm'&&str[i] <= 'o')

              {

                    str[i] = '6';

              }elseif(str[i] >= 'p'&&str[i] <= 's')

              {

                    str[i] = '7';

              }elseif(str[i] >= 't'&&str[i] <= 'v')

              {

                    str[i] = '8';

              }elseif(str[i] >= 'w'&&str[i] <= 'z')

              {

                    str[i] = '9';

              }elseif(str[i] >= 'A'&&str[i] <= 'Y')

              {

                    str[i] = str[i] + 'a'- 'A'+1;

              }elseif(str[i] == 'Z')

              {

                    str[i] = 'a';

              }

            i++;

        }

        cout<<str<<endl;

    }

    return0;

}

朋友圈转发信息

输出:	当某用户发布一条信息之后，为了让每个人都能在最早时间收到这条信息，这条信息最少需要被转发的次数
样例输入:	Sender 1 Relationship 1,2 1,3 1,4 2,5 2,6 3,6 4,6 4,7 5,6 5,8 5,9 6,7 6,8 6,9 7,9 10,7 End
样例输出:	4

#include <cstdio>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <map>
#include <set>
using namespace std;
/*
    suppose every person has been labeled by a unique positive number
*/
int sponsor;                //the news sender
map<int, set<int> > friends;//relationship graph, use set to avoid repeated edges


map<int, int> dis;          //each person's shortest distance to sponsor
queue<int> q;               //used in spfa
map<int, bool> inq;         //used in spfa


vector<vector<int> > level; //group people with same distance to sponsor


int fromLevel, forwards;    //used in DFS to find minimum forwards needed between fromLevel to fromLevel + 1
map<int,int> toldBy;        //used in DFS to mind each person's teller in previous level


void input()
{
    string line;
    int x, y;
//input sender
    getline(cin, line);
    cin >> sponsor;
    getline(cin, line);
//input relationship
    getline(cin, line);
    while(getline(cin, line), line != "End"){
        sscanf(line.c_str(), "%d,%d", &x, &y);//undirected graph
        friends[x].insert(y);
        friends[y].insert(x);
    }
}
void spfa()
{
//initialize 
    for(map<int, set<int> >::iterator iter = friends.begin(), eter = friends.end(); 
        iter != eter; 
        ++iter){
        dis[iter->first] = friends.size();
        inq[iter->first] = false;
    }
    dis[sponsor] = 0;
    q.push(sponsor);
    inq[sponsor] = true;
//relax process
    set<int>::iterator iter, eter;
    while(!q.empty()){
        int x = q.front();
        q.pop();
        inq[x] = false;
        iter = friends[x].begin(); eter = friends[x].end();
        for(; iter != eter; ++iter){
            int y = *iter;
            if(dis[y] > dis[x] + 1){
                dis[y] = dis[x] + 1;
                if(!inq[y]){
                    q.push(y);
                    inq[y] = true;
                }
            }
        }
    }
}
void separate()
{
    map<int, int>::iterator iter = dis.begin(), eter = dis.end();
//there are maxDistance + 1 levels
    level.resize(dis.rbegin()->second + 1);
    for(; iter != eter; ++iter){
        level[iter->second].push_back(iter->first);
    }
}
bool allKnown()
{
    map<int,int>::iterator iter = toldBy.begin(), eter = toldBy.end();
    for(; iter != eter; ++iter){
        if(0 == iter->second) return false;
    }
    return true;
}
void post(int teller, set<int>& peer)
{
    set<int>::iterator iter = peer.begin(), eter = peer.end();
    map<int,int>::iterator ater = toldBy.begin(), bter = toldBy.end();
    for(; iter != eter; ++iter){
        ater = toldBy.find(*iter);//*iter might not in this level
        if(ater != bter && ater->second == 0) ater->second = teller;
    }
}
void undo(int teller, set<int>& peer)
{
    set<int>::iterator iter = peer.begin(), eter = peer.end();
    map<int,int>::iterator ater = toldBy.begin(), bter = toldBy.end();
    for(; iter != eter; ++iter){
        ater = toldBy.find(*iter);//*iter might not in this level
        if(ater != bter && ater->second == teller) ater->second = 0;
    }
}
void dfs(int index, int doPost)
{
    if(index < 0){
        if(allKnown() && doPost < forwards) forwards = doPost;
        return;
    }
//if this person do not make a forward
    dfs(index - 1, doPost);
//if this person do a forward
    post(level[fromLevel][index], friends[level[fromLevel][index]]);
    dfs(index - 1, doPost + 1);
    undo(level[fromLevel][index], friends[level[fromLevel][index]]);
}
int getMinimumForwards()
{
//because the sponsor's post does not count, we dont need to calculate forwards between level 0 and level 1
//though it is just 1, as we have only one sponsor
    int sum = 0, i = 2, n = level.size();
//find minimum forwards needed between each adjacent levels, 1->2, 2->3, ...
    for(; i < n; ++i){
    //at most each person in this level make a forward
        fromLevel = i - 1;
        forwards = level[fromLevel].size();
    //set known flags of all people in next level to be false
        toldBy.clear();
        const vector<int>& v = level[i];
        for(int j = 0, m = v.size(); j < m; ++j){
            toldBy[v[j]] = 0;//insert and set value
        }
    //DFS to find best result
        dfs(level[fromLevel].size() - 1, 0);
        sum += forwards;
    }
    return sum;
}


int main()
{
/* read input */
    input();
/* find out each person's shortest distance to sponsor */
    spfa();
/* separate each group by distance to sponsor */
    separate();
/* find out minimum forwards */
    printf("%d\n", getMinimumForwards());
}