Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> merge(vector<Interval> &intervals) {
vector<Interval> res;
for (int i = 0; i < intervals.size(); i++) {
insert(res, intervals[i]);
}
return res;
}
void insert(vector<Interval> &res, Interval newInterval) {
auto it = res.begin();
while (it != res.end()) {
if (newInterval.end < it->start) {
res.insert(it, newInterval);
return ;
} else if (newInterval.start > it->end) {
it++;
continue;
} else {
newInterval.start = min(newInterval.start, it->start);
newInterval.end = max(newInterval.end, it->end);
it = res.erase(it);
}
}
res.push_back(newInterval);
}
};