[leetcode 71] Simplify Path

最新推荐文章于 2022-04-02 15:05:46 发布

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最新推荐文章于 2022-04-02 15:05:46 发布

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分类专栏： [LeetCode 刷题] 文章标签： leetcode stack

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本文介绍了一个C++程序，用于简化Unix风格的绝对路径。通过解析输入路径并移除多余的符号如'..'和'.',最终返回规范化的路径字符串。讨论了特殊情况处理，例如连续的斜杠及路径起始为'../'的情况。

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

click to show corner cases.

Corner Cases:

Did you consider the case where path = "/../"?
In this case, you should return "/".
Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
In this case, you should ignore redundant slashes and return "/home/foo".

class Solution {
public:
    string simplifyPath(string path) {
        vector<string> simplePath;
        auto last = path.end();
        for (auto i = path.begin(); i != last; ) {
            i++;
            auto j = find(i, last, '/');
            auto tmp = string(i,j);
            if (!tmp.empty() && tmp != ".") {
                if (tmp == "..") {
                    if (!simplePath.empty()) {
                        simplePath.pop_back();
                    }
                } else {
                    simplePath.push_back(tmp);
                }
            }
            i = j;
        }
        string res ;
        if (simplePath.empty()) {
            return "/";
        }
        for (auto i : simplePath) {
            res += "/" + i;
        }
        return res;
    }
};