DateTime.Now.ToString() 输出格式化_datetime.now.tostring("hh:mm")-优快云博客

本文介绍了使用C#进行日期时间格式化的多种方法，包括如何利用不同的格式字符串来获取特定形式的时间显示，如完整的日期时间格式、仅日期、仅时间等。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

string dt=System.DateTime.Now.ToString("yyyy-MM-dd");
string dt1=System.DateTime.Now.ToString("HH:mm");
string dt2=System.DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss");
HH为24小时制,hh为12小时制

using System;
using System.Globalization;
public class MainClass
{
　　public static void Main(string[] args)
　　{
DateTime dt = DateTime.Now;
String[] format = {"d","D","f","F","g","G","m","r","s","t", "T","u", "U","y","dddd, MMMM dd yyyy","ddd, MMM d \"'\"yy","dddd, MMMM dd","M/yy","dd-MM-yy",};
String date;
for (int i = 0; i < format.Length; i++)
{
date = dt.ToString(format[i], DateTimeFormatInfo.InvariantInfo);
Console.WriteLine(String.Concat(format[i], " :" , date));
}
}
}
d :07/11/2004 <=======输出
D :Sunday, 11 July 2004
f :Sunday, 11 July 2004 10:52
F :Sunday, 11 July 2004 10:52:36
g :07/11/2004 10:52
G :07/11/2004 10:52:36
m :July 11
r :Sun, 11 Jul 2004 10:52:36 GMT
s :2004-07-11T10:52:36
t :10:52
T :10:52:36
u :2004-07-11 10:52:36Z
U :Sunday, 11 July 2004 02:52:36
y :2004 July
dddd, MMMM dd yyyy :Sunday, July 11 2004
ddd, MMM d "'"yy :Sun, Jul 11 '04
dddd, MMMM dd :Sunday, July 11
M/yy :7/04
dd-MM-yy :11-07-04