题目链接:https://leetcode.com/problems/serialize-and-deserialize-binary-tree/description/
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
For example, you may serialize the following tree
1 / \ 2 3 / \ 4 5as
"[1,2,3,null,null,4,5]"
, just the same as
how LeetCode OJ serializes a binary tree
. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
Credits:
Special thanks to @Louis1992 for adding this problem and creating all test cases.
class Codec{
public:
string serialize(TreeNode* root)
{
if (!root) return " #";
string res=" "+to_string(root->val);
return res+serialize(root->left)+serialize(root->right);
}
TreeNode* dfs(istringstream &is)
{
string str;
is>>str;
if(str=="#") return NULL;
TreeNode* root=new TreeNode(stoi(str));
root->left=dfs(is);
root->right=dfs(is);
return root;
}
TreeNode* deserialize(string data)
{
istringstream is(data);
return dfs(is);
}
};
class Codec {
public:
// Encodes a tree to a single string.
string serialize(TreeNode* root) {
if (root == nullptr) return "#";
return to_string(root->val)+","+serialize(root->left)+","+serialize(root->right);
}
// Decodes your encoded data to tree.
TreeNode* deserialize(string data) {
return mydeserialize(data);
}
TreeNode* mydeserialize(string& data) {
if (data[0]=='#') {
if(data.size() > 1) data = data.substr(2);
return nullptr;
} else {
TreeNode* node = new TreeNode(helper(data));
node->left = mydeserialize(data);
node->right = mydeserialize(data);
return node;
}
}
private:
int helper(string& data) {
int pos = data.find(',');
int val = stoi(data.substr(0,pos));
data = data.substr(pos+1);
return val;
}
};