2-6 让字典保持有序

# -*- coding:utf-8 -*-

from collections import OrderedDict
from time import time
from random import randint

# 问题如下：
d = {}
d['Jim'] = (1, 35)
d['Leo'] = (2, 37)
d['Bob'] = (3, 40)

for k in d: print k
# 结果：
# Bob
# Jim
# Leo
# 以上输出表示程序并不维护字典元素的先后进入顺序

# 解决方案：
d = OrderedDict()
d['Jim'] = (1, 35)
d['Leo'] = (2, 37)
d['Bob'] = (3, 40)

for k in d: print k
# Jim
# Leo
# Bob

# 具体例子：
o_d = OrderedDict()
players = list('ABCDEFGH')
start = time()

for i in xrange(8):
    raw_input()
    p = players.pop(randint(0, 7-i))
    end = time()
    print i + 1, p, end - start,
    o_d[p] = (i + 1, end - start)

print        # 因为上面的print语句后面有 , 号，如果不加这句下面将会在上面输出结果后面直接紧接着输出
print '*' * 20     # 这种形式很有意思

for k in o_d:               # k 为 d 中的 key
    print k, o_d[k]