题目:
Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.
+----+-------+ | Id | Score | +----+-------+ | 1 | 3.50 | | 2 | 3.65 | | 3 | 4.00 | | 4 | 3.85 | | 5 | 4.00 | | 6 | 3.65 | +----+-------+
For example, given the above Scores
table,
your query should generate the following report (order by highest score):
+-------+------+ | Score | Rank | +-------+------+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +-------+------+
# Write your MySQL query statement below
#见参考方法
select t.Score,
(select count(s.Score)+1 from (select s.Score,count(s.Score) from Scores s group by s.Score order by s.Score desc) s where s.Score>t.Score) Rank
from Scores t
order by t.Score desc;
参考方法:
1 1 3 4排名方式
mysql> select * from score;
+----+-------+| id | Score |
+----+-------+
| 1 | 36.5 |
| 2 | 37.8 |
| 3 | 40.6 |
| 4 | 42.6 |
| 5 | 36.5 |
| 6 | 36.5 |
| 7 | 42.6 |
| 8 | 40.6 |
| 9 | 22.8 |
| 10 | 42.6 |
+----+-------+
10 rows in set
mysql> select t.score,(select count(s.score)+1 from score s where s.score>t.score) rank from score t order by t.score desc;
+-------+------+
| score | rank |
+-------+------+
| 42.6 | 1 |
| 42.6 | 1 |
| 42.6 | 1 |
| 40.6 | 4 |
| 40.6 | 4 |
| 37.8 | 6 |
| 36.5 | 7 |
| 36.5 | 7 |
| 36.5 | 7 |
| 22.8 | 10 |
+-------+------+
10 rows in set
1 1 2 3 排序方式
mysql> select t.score,(select count(s.score)+1 from (select s.score,count(s.score) from score s group by score order by score desc) s where s.score>t.score) rank from score t order by t.score
desc;
+-------+------+
| score | rank |
+-------+------+
| 42.6 | 1 |
| 42.6 | 1 |
| 42.6 | 1 |
| 40.6 | 2 |
| 40.6 | 2 |
| 37.8 | 3 |
| 36.5 | 4 |
| 36.5 | 4 |
| 36.5 | 4 |
| 22.8 | 5 |
+-------+------+
10 rows in set