题目:
Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation.
For example:
Given "aacecaaa"
, return "aaacecaaa"
.
Given "abcd"
, return "dcbabcd"
.
翻转后找相等的最大前后缀,没优化,应该可以不用翻转,直接比较。
class Solution {
public:
string shortestPalindrome(string s) {
string t = s;
reverse(t.begin(),t.end());
if(t == s) return t;
int i = t.size()-1;
for( ;i >=0;i--){
if(t.substr(t.size()-1-i,i)==s.substr(0,i)) {
break;
}
}
return t.substr(0,t.size()-1-i) + s;
}
};
最优:
class Solution {
public:
string shortestPalindrome(string s) {
int n = s.length();
int i = 0, j = n - 1;
while (j >= 0) {
if (s[i] == s[j]) ++i;
--j;
}
if (i == n) return s;
string suffix = s.substr(i);
return string(suffix.rbegin(), suffix.rend()) + shortestPalindrome(s.substr(0, i)) + suffix;
}