1154 Vertex Coloring (25 分)

本文探讨了图论中的k-着色问题,详细解释了如何判断一个图是否可以进行k-着色,并提供了具体的算法实现。通过检查每条边的两个顶点颜色是否相同,来验证给定的颜色分配是否有效。

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proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.

Now you are supposed to tell if a given coloring is a proper k-coloring.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 10​4​​), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.

After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.

Output Specification:

For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.

Sample Input:

10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9

Sample Output:

4-coloring
No
6-coloring
No

题意是问是否每条边的两个顶点都是不同颜色的顶点,如果是输出颜色种类,不是输出NO

可以用结构体数组来存储相连的边,根据输入的顶点的颜色来进行判断对应的点

#include<bits/stdc++.h>
using namespace std;
struct node
{
    int t1,t2;
};
int main()
{
    int n,m,k;
    cin>>n>>m;
    vector<node>v(m);
    for(int i=0;i<m;i++)
    {
        scanf("%d %d", &v[i].t1, &v[i].t2);
    }
    cin>>k;
    while(k--)
    {
        int a[10005]={0},flag=1;
        set<int>ans;
        for(int i=0;i<n;i++)
        {
            scanf("%d", &a[i]);
            ans.insert(a[i]);
        }
        for(int i=0;i<m;i++)
        {
            if(a[v[i].t1]==a[v[i].t2])
            {
                flag=0;
                break;
            }
        }
        if(flag)
            printf("%d-coloring\n", ans.size());
        else
            printf("No\n");
    }
    return 0;
}
 

记着一定要return 0 

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