遍历json（迭代）

最新推荐文章于 2024-09-23 13:59:04 发布

数据交互

最新推荐文章于 2024-09-23 13:59:04 发布

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分类专栏： Jquery 文章标签：数据遍历 json 迭代

本文链接：https://blog.youkuaiyun.com/wsluben/article/details/47759409

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本文介绍了在处理复杂JSON数据时，如何使用迭代来有效地解析和获取特定类型的节点，例如获取所有table类型的节点。通过迭代，可以更方便地处理包含广泛内容的JSON，并存储具有唯一性的键。

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json做数据交互很方便，平时写起来有些类似map，这次解析一个包含内容较广的json时发现原来的方法不适用，单纯用for循环没有解决，在网上找资料实践了下发现还是迭代合适，比如需要解析的如下json获取table类型的node

{"title":"newFlow_1",
"nodes":{
        "demo_node_1":{"name":"SQL条件选择","left":86,"top":66,"type":"sqlcondition","width":60,"height":20,"alt":true},
        "demo_node_2":{"name":"排序","left":464,"top":72,"type":"sort","width":60,"height":20,"alt":true},
        "demo_node_5":{"name":"Table","left":690,"top":139,"type":"table","width":60,"height":20,"alt":true},
        "demo_node_8":{"name":"Table","left":230,"top":240,"type":"table","width":60,"height":20,"alt":true},"demo_node_11":{"name":"排序","left":467,"top":164,"type":"sort","width":60,"height":20,"alt":true},"demo_node_13":{"name":"Table","left":661,"top":247,"type":"table","width":60,"height":20,"alt":true}},
"lines":{
        "demo_line_3":{"type":"sl","from":"demo_node_1","to":"demo_node_2","name":""},
        "demo_line_6":{"type":"sl","from":"demo_node_2","to":"demo_node_5","name":""},
        "demo_line_9":{"type":"sl","from":"demo_node_1","to":"demo_node_8","name":""},
        "demo_line_12":{"type":"sl","from":"demo_node_1","to":"demo_node_11","name":""},
        "demo_line_14":{"type":"sl","from":"demo_node_11","to":"demo_node_13","name":""}},
"areas":{},"initNum":17}

先解析出table类型的node

JSONObject dataJson = new JSONObject().fromObject(jsonStr);
JSONObject nodes = dataJson.getJSONObject("nodes");

然后迭代匹配table类型节点，将区分唯一性的key存储起来

List<String> nodeNameJsonList = new ArrayList<String>();
Iterator it = nodes.keys();
while(it.hasNext()){
            String key = (String) it.next();// "demo_node_1"
            JSONObject node = nodes.getJSONObject(key);
            String nodeStr = node.toString();
            if(nodeStr!=null){
                nodeType = node.getString("type");
                if("table".equals(nodeType)){
                    nodeNameJsonList.add(key);
                }
            }
        }

最后结果为：

[demo_node_5, demo_node_8, demo_node_13]