malloc总结:
https://blog.youkuaiyun.com/a351945755/article/details/20142809
int m = 2;
int n = 3;
int i;
//二位数组a[m][n]
int **a;
a = (int **) malloc(m * sizeof(int *));
for(i=0; i<m; ++i)
{
a[i] = (int *) malloc(n * sizeof(int));
}
memset(a, 0, sizeof(int) * m * n);
(稍后补充)