python 判断是否为函数

最新推荐文章于 2023-11-01 11:03:19 发布

word1000

最新推荐文章于 2023-11-01 11:03:19 发布

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文章标签： word1000

本文链接：https://blog.youkuaiyun.com/word1000/article/details/18767105

本文介绍了一个使用Python编写的代码解析器，该解析器能够读取指定目录下的C语言源文件，并从中提取函数定义进行打印输出。通过对源代码的逐行分析，判断是否为死代码或者函数定义头部，从而实现对C语言函数的有效识别。

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import os

functionHead = ['U32','U16', 'VOI']

deadCodeFlag = 0
endIfFlag = 0

def isDeadCode(string):
        global deadCodeFlag
        global endIfFlag
        if deadCodeFlag == 0:
                endIfFlag = 0
                if "#if 0" in string:
                        deadCodeFlag = 1                        
        else:
                if "#endif" in string:
                        deadCodeFlag = 0
                        endIfFlag = 1

def isFunction(string):
        isFunctionFlag = 0
        isDeadCode(string)
        if (deadCodeFlag == 0) and (endIfFlag == 0):
                if len(string) >= 5 and (string[0:3] in functionHead):
                        isFunctionFlag = 1
        return isFunctionFlag

def printFunctionInFile(filename):
        filestyle = filename.split('.')
        if filestyle[1] == 'c':
                fp = open(filename, 'r+')
                lines = fp.readlines()
                for index, line in enumerate(lines):
                        if isFunction(line) == 1:
                                if line.endswith("\\\n"):
                                        print line + lines[index + 1]
                                else:
                                        print line
if __name__ == '__main__':
        filenames = os.listdir(os.curdir)
        for filename in filenames:
                printFunctionInFile(filename)