关于人事岗位变动（适用于bom）

--http://blog.youkuaiyun.com/wlzd3636
--关于人事软件中的员工岗位调整
--员工岗位表
if object_id(N'jobcode','U') is not null
drop table jobcode;
create table jobcode
(id  smallint identity(1,1) ,
 jobcode char(5) not null,
 jobname varchar(20) not null,
 superiorjobcode char(5) not null
)
--生成测试数据
insert into jobcode(jobcode,jobname,superiorjobcode)
  select jobcode='hrp01',jobname=N'人事总监',superiorjobcode=''
  union all
  select 'hrp02',N'人事副总监','hrp01'
  union all
  select 'hrp03',N'人事经理','hrp02'
  union all
  select 'hrp04',N'idc人事','hrp03'
  union all
  select 'hrp05',N'运维人事','hrp03'
  union all
  select 'omp01',N'运维总监',''
  union all
  select 'omp02',N'运维副总监','omp01'
  union all
  select 'omp03',N'运维经理','omp02'
  union all
  select 'omp04',N'运维idc主管','omp03'
  union all
  select 'omp05',N'运维db主管','omp03'
  union all
  select 'omp06',N'运维idc','omp04'
  union all
  select 'omp07',N'运维db','omp05'
 go
--员工信息表
if object_id(N'jobinfo','U') is not null
drop table jobinfo;
create table jobinfo
(id  int identity(1,1),
 name varchar(20) not null,
 jobcode char(5) not null,
 senior varchar(20) not null
);
--生成测试数据
insert into jobinfo(name,jobcode,senior)
  select name='hrjob_a', jobcode='hrp01',senior=''
  union all
  select 'hrjob_b','hrp02','hrjob_a'
  union all
  select 'hrjob_c','hrp03','hrjob_b'
  union all
  select 'hrjob_d','hrp04','hrjob_c'
  union all
  select 'hrjob_e','hrp05','hrjob_c'
  union all
  select 'ompjob_a','omp01',''
  union all
  select 'ompjob_b','omp02','ompjob_a'
  union all
  select 'ompjob_c','omp03','ompjob_b'
  union all
  select 'ompjob_d','omp04','ompjob_c'
  union all
  select 'ompjob_e','omp05','ompjob_c'
  union all
  select 'ompjob_f','omp06','ompjob_d'
  union all
  select 'ompjob_h','omp07','ompjob_e'
 go

--常用统计
返回每个员工下面的下级员工
--2005
if object_id(N'bom_job','IF') is not null
drop function bom_job;
create function bom_job(@name varchar(20)) returns table
as
return
with xwj
as
(select a.id,a.name,a.jobcode,a.senior,b.jobname
  from jobinfo as a
  inner join jobcode as b 
  on a.jobcode=b.jobcode
),
xwj2
as
(select id,name,jobcode,senior,@name as maxsenior,jobname from xwj where name=@name
 union all 
 select b.id,a.name,a.jobcode,b.name as senior,maxsenior=@name,a.jobname from xwj as a inner join xwj2 as b on b.name=a.senior
)
select * from xwj2
go
--演示
select b.* 
 from jobinfo as a 
 cross apply
 bom_job(a.name) as b
 where a.name='hrjob_b'
/*
id   name   jobcode senior      maxsenior         jobname
----------- -------------------- ------- -------------------- 
2   hrjob_b  hrp02   hrjob_a   hrjob_b            人事副总监
2   hrjob_c  hrp03   hrjob_b   hrjob_b              人事经理
2   hrjob_d  hrp04   hrjob_c   hrjob_b              idc人事
2   hrjob_e  hrp05   hrjob_c   hrjob_b              运维人事

(4 行受影响)
*/
一般在薪筹软件里员工变动很大比如
人事总监hrjob_a 换岗到运维部当 运维经理
而运维经理ompjob_c 换岗到人事部门当人事总监则
原表里面的数据以及下属员工的上级数据都得变动
为了演示
从新生成了一个临时表
--生成数据
select * into #jobcode
 from jobcode
select * into #jobinfo
 from jobinfo

select * from #jobcode

select *from #jobinfo
--思路
找出原先运维经理的一级下属，和直接上司
找出原先人事总监一级下属和直接上司

--需一中间表

select a.*,b.jobname
into # 
from #jobinfo as a  inner join #jobcode as b on a.jobcode=b.jobcode

with 
xwj
as
(
select name,jobcode,senior,jobname,id=0 from # where name='ompjob_c'
union all
select a.name,a.jobcode,a.senior,a.jobname,b.id+1 from  # as a inner join xwj as b on b.name=a.senior
 )
,
xwj2
as
(select name,jobcode,senior,jobname,id=0 from # where name='ompjob_c'
 union all
 select a.name,a.jobcode,a.senior,a.jobname,b.id-1 from  # as a inner join xwj2 as b on a.name=b.senior
)
,
xwj3
as
(select * from xwj
 union
 select * from xwj2
)
select * from xwj3 where id=1 or id=-1

--分别update
建议:
--2005 xml
用xml 来存储一个部门或组的员工信息


declare @xml xml
select @xml=
'<company company_depart="尚瑞薪才">
  <deport deportname="人事">
    <job name="hrjob_a" jobcode="hrp01" senior="" jobname="人事总监"/>
  </deport>
  <deport deportname="运维">
    <job name="ompjob_a" jobcode="omp01" senior="" jobname="运维总监"/>
  </deport>
</company>'
select @xml

 

eg:

create table company_xml
(id smallint identity(1,1),
 part xml not null
)

insert into company_xml(part)
values(
cast('<company company_depart="尚瑞薪才">
  <deport deportname="人事">
    <job name="hrjob_a" jobcode="hrp01" senior="" jobname="人事总监"/>
    <job name="hrjob_b" jobcode="hrp02" senior="hrjob_a" jobname="人事副总监"/>
  </deport>
</company>' as xml)
)

insert into company_xml(part)
values(
cast('<company company_depart="尚瑞薪才">
  <deport deportname="运维">
    <job name="ompjob_a" jobcode="omp01" senior="" jobname="运维总监"/>
    <job name="ompjob_b" jobcode="omp02" senior="ompjob_b" jobname="运维副总监"/>
  </deport>
</company>' as xml)
)


select  company_depart,deportname,name,jobcode,senior,jobname from company_xml  as a
cross apply
(
select  t.c.value('@company_depart','sysname') as company_depart,
        t.c.value('(deport/@deportname)[1]','sysname') as deportname
     from a.part.nodes('/company') as t(c)
) as b
cross apply
( select * from
   (select id,b.name,b.jobcode,b.senior,b.jobname
      from
        (select id,part.query('/company/deport/job') as job
          from  company_xml) as a
         cross apply
         (select   
              t.c.value('@name','sysname') as name,
              t.c.value('@jobcode','sysname') as jobcode,
              t.c.value('@senior','sysname') as senior,
              t.c.value('@jobname','sysname') as jobname
             from a.job.nodes('/job')  as t(c)
          )as b ) as c 
   where a.id=c.id
)as d


如图:
company_depart deportname     name        jobcode        senior       jobname

尚瑞薪才			人事		hrjob_a		hrp01  			人事总监
尚瑞薪才			人事		hrjob_b		hrp02	hrjob_a	  人事副总监
尚瑞薪才			运维		ompjob_a     omp01		     运维总监
尚瑞薪才			运维		ompjob_b    omp02   ompjob_b 运维副总监
 
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