struts2+ext.js中对json的个人理解_struts2.5 action extjs4 tree json格式问题-优快云博客

本文介绍如何在 Struts2 框架中配置 JSON 插件并实现数据交互，通过示例展示如何定义 struts.xml 中的包及 action 来处理 JSON 数据，并返回 JSON 格式的数据列表。

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在处理json对象时

struts.xml的配置

<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">

<struts>

<package name="dept" namespace="/" extends="json-default">

<action name="deptListAction" class="com.hydz.action.DeptAction" method="find">
<result name="json-deptList" type="json">
</result>
</action>
</package>

</struts>

@Controller
public class DeptAction extends ActionSupport{
@Resource
private DeptService deptService;
private Dept dept;
private int total;
private Boolean success;
private List<Dept> deptList;
public String find() {
deptList=deptService.find();
total=deptList.size();
success=true;
//JSONObject jo=new JSONObject();
//JSONArray ja = JSONArray.fromObject(deptList);
//deptList=jo.put("deptlist", ja);//.toString();
return "json-deptList";

}public int getTotal() {
return total;
}

public void setTotal(int total) {
this.total = total;
}
public DeptService getDeptService() {
return deptService;
}
public void setDeptService(DeptService deptService) {
this.deptService = deptService;
}
public Dept getDept() {
return dept;
}
public void setDept(Dept dept) {
this.dept = dept;
}
public List<Dept> getDeptList() {
return deptList;
}
public void setDeptList(List<Dept> deptList) {
this.deptList = deptList;
}
public Boolean getSuccess() {
return success;
}
public void setSuccess(Boolean success) {
this.success = success;
}
}