A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.
The tournament takes place in the following way (below, m is the number of the participants of the current round):
- let k be the maximal power of the number 2 such that k ≤ m,
- k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly,
- when only one participant remains, the tournament finishes.
Each match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.
Find the number of bottles and towels needed for the tournament.
Note that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).
The only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.
Print two integers x and y — the number of bottles and towels need for the tournament.
5 2 3
20 15
8 2 4
35 32
In the first example will be three rounds:
- in the first round will be two matches and for each match 5 bottles of water are needed (two for each of the participants and one for the judge),
- in the second round will be only one match, so we need another 5 bottles of water,
- in the third round will also be only one match, so we need another 5 bottles of water.
So in total we need 20 bottles of water.
In the second example no participant will move on to some round directly.
#!/usr/bin/python
# -*-coding:utf-8 -*-
def get_k(a):
i=0
while(pow(2,i)<a):
i+=1
if i>1:
return i-1
else:
return i
n,b,p=map(int,raw_input().split(' '))
towels=n*p
bottles=0
while(n>1):
k=get_k(n)
bottles=bottles+k*b*2+k
n=n-k
print "%d %d"%(bottles,towels)
本文介绍了一个网球锦标赛中所需物资(水瓶和毛巾)的计算方法。通过特定算法确定每轮比赛的人数,进而计算出整个赛事所需的总物资数量。
474

被折叠的 条评论
为什么被折叠?



