阿里笔试学习：题目大意：给出大小为n ∗ m n*mn∗m的01矩阵，从每个0的位置上下左右看，问所有在位置上下左右看一共能看到多少个1.(视线是一条直线)n , m ＜ = 1 e 3 n,m＜=

# -*- coding : utf-8 -*-
# @Time      : 2022/10/2 23:05
# @Author    : wkb
matrix = [[1,0,1],
          [0,1,1],
          [1,0,0]]
matrix_t = []
for i in zip(*matrix):
    matrix_t.append(list(i))
m = len(matrix)
n = len(matrix[0])
count = 0
for i in range(m):
    for j in range(n):
        if(matrix[i][j] == 0):
            temp_row = str(matrix[i])
            count = count+temp_row.count('1')
            temp_col = str(matrix_t[j])
            count = count+temp_col.count('1')
print(count)

利用zip（*matrix）进行转置