笨办法学python3——习题32

the_count = [1, 2, 3, 4, 5]
fruits = ['apples', 'oranges', 'pears', 'apricots']
change = [1, 'pennies', 2, 'dimes', 3, 'quarters']

# this first kind of for-loop goes through a list
for number in the_count:
    print(f"This is count {number}")

# same as above
for fruit in fruits:
    print(f"A fruit of type:{fruit}")

# also, we can go through mixed lists to
# notice we have to use {} since we don't know what's in it
for i in change:
    print(f"I got {i}")

# we can also build lists, first start with an empty one
elements = []

# then use the range function to do 0 to 5 counts
for i in range(0, 6):  # i从0数到5
    print(f"Adding {i} to the list.")
    # append is a function that lists understand
    elements.append(i)  # 在elements列表尾部追加元素

    # now we can print them out too
for i in elements:
    print(f"Elements was: {i}")

本题首先实现了通过循环结构将列表中的元素依次打印出来，然后构建了一个空的列表，通过elements.append( )在列表尾部依次追加元素，再将这个新列表中的元素依次打印出来。