求满足条件的爱因斯坦阶梯的最小值

#include <stdio.h>
#include<stdlib.h>
int main()
{
	int n=7;
	while(1)
	{
		if(n%2==1&&n%3==2&&n%4==3&&n%5==4&&n%6==5)
			break;
		n+=7;
	
	
	}
	printf("%d\n",n);
	system("pause");
	  

	
}