矩阵乘法（C语言）

        最近在做多线程矩阵乘法实验，下面是单线程下矩阵乘法的实现，也就是用朴素矩阵乘法算法求C=A*B。代码支持自定义输入A、B的值，便于观看和理解，代码里写了很多注释和输出反馈，后续多线程会删掉，有兴趣的朋友关注一波~

        运行实例在末尾，下面是完整代码~

#include <stdio.h>
#include <stdlib.h>

#define ROW 20
#define COL 20

//print matrix
void printmatrix(int C[ROW][COL],int row,int col)
{
        printf("\n---MATRIX ELEMENTARY START---\n");
        for(int i=0;i<row;i++)
        {
                for(int j=0;j<col;j++)
                {
                        printf("%5d  ",C[i][j]);
                }
                printf("\n");
        }
        printf("\n---MATRIX ELEMENTARY END---\n");
}

int main(int argc,char *argv[])
{
        int A[ROW][COL]={0};
        int B[ROW][COL]={0};
        int C[ROW][COL]={0};
        int row1,col1,row2,col2;

        //matrix A input
        printf("\n---please input you row-col number of A--\n ");
        scanf("%d-%d\n",&row1,&col1);
        printf("Now input you elementary of matrix A:\n");
        for(int i=0;i<row1;i++)
        {
                for(int j=0;j<col1;j++)
                {
                        scanf("%d",&A[i][j]);
                }
        }
        printf("---Input of A done!---\n");
        printmatrix(A,row1,col1);
        printf("\n");

        //matrix B input
        printf("---please input you row-col number of B--\n ");
        scanf("%d-%d\n",&row2,&col2);
        printf("Now input you elementary of matrix B:\n");
        for(int i=0;i<row2;i++)
        {
                for(int j=0;j<col2;j++)
                {
                        scanf("%d",&B[i][j]);
                }
        }
        printf("---Input of B done!---\n");
        printmatrix(B,row2,col2);
        printf("\n");

        //accumulate judge and matrix C count
        if(col1!=row2)
                printf("illegal to multiply:colA!=rowB\n");
        else
        {
                for(int i=0;i<row1;i++)
                {
                        for(int j=0;j<col2;j++)
                        {
                                for(int k=0;k<col1;k++)
                                {
                                        C[i][j]+=A[i][k]*B[k][j];
                                }
                        }
                }
        }
        printf("---accumulate of C=A*B done!---\n");
        printmatrix(C,row1,col2);
        printf("\n");

        return 0;

}

         运行实例如下：