洛谷P5707 【深基2.例12】上学迟到进阶解法

#include<cstdio>
#include<cmath>

using namespace std;
int s, v;

int main()
{
	int min, hour;
	scanf("%d%d", &s, &v);
	min = ceilf(double(s) / v + 10);
	hour = 7 - min / 60;
	if (hour < 0)
		hour += 24;
	min %= 60;
	min = 60 - min;
	printf("%02d:%02d", hour, min);
	return 0;
}