选择排序
#include<iostream>
using namespace std;
const int N = 100010;
int a[N];
int n;
int main()
{
cin >> n;
for(int i = 0; i < n; i ++) scanf("%d", &a[i]);
for(int i = 0; i < n; i ++)
{
int k = i;
for(int j = i + 1; j < n; j ++)
{
if(a[k] > a[j]) k = j;
}//循环完以后k为数组最小值下标
if(k != i)
{
int t = a[k];
a[k] = a[i];
a[i] = t;
}
}
for(int i = 0; i < n; i ++) printf("%d ",a[i]);
return 0;
}
最优和最差时间复杂度都为 O(n^2)
之前没有写const,一直[Error] array bound is not an integer constant before ‘]’ token,一大堆a数组未定义的错误提示,涨知识辽(依然欢迎小伙伴指出错误哈