模拟 inner join:归并的思路
#include<bits/stdc++.h>
using namespace std;
int main(){
vector<pair<int,char>> list1 ={{1,'a'},{2,'b'},{2,'c'},{3,'d'}};
vector<pair<int,char>> list2 ={{1,'e'},{2,'f'},{3,'g'},{4,'h'}};
int p1=0,p2=0,p3;
int n1= list1.size(),n2=list2.size();
int vis_idx=-1 ;
vector<tuple<int,char,char>> res;
while(p1!=n1 and p2!=n2){
auto tup1=list1[p1],tup2=list2[p2];
int k1 = tup1.first,k2=tup2.first;
char v1= tup1.second,v2=tup2.second;
if(k1==k2){
res.emplace_back(k1,v1,v2);
p3 = p1+1;
while(p3<n1 and list1[p1].first==list1[p3].first){
res.emplace_back(k1,list1[p3].second,v2);
vis_idx = p3;
p3++;
}
p2++;
}else if(k1>k2) {
p2++;
}else if(k1<k2){
p1++;
while(p1<=vis_idx){
p1++;
}
}
}
for(auto p:res){
std::cout << std::get<0>(p)<<get<1>(p)<<get<2>(p)<<endl;
}
}