Python基础五个题

1.题
有如下值集合[11,22,33,44,55,66,77,88,99,90], 将所有大于66的值保存至字典的第一个key中，将小于66值保存至第二个key的值

li = [11, 22, 33, 44, 55, 66, 77, 88, 99, 90]
dic = {}
list_1 = []  # 大于66
list_2 = []  # 小于66
for i in li:
    if i == 66:
        continue
    if i > 66:
        list_1.append(i)
    else:
        list_2.append(i)
dic.setdefault('k1', list_1)
dic.setdefault('k2', list_2)
print(dic)

2.题
输出商品列表，用户输入序号，显示用户选中的商品。
商品 li = [“手机”, “电脑”, “鼠标垫”, “游艇” ]

a. 允许用户添加商品

b. 用户输入序号显示内容

li = [“手机”, “电脑”, "鼠标

垫", "游艇" ]
mer = input("请输入您想加入的商品:")
li.append(mer)
print("商品现有",li)
wan = int(input("请输入序号："))
print(li[wan-1])

3.题（自由发挥）
用户交互显示类似省市县N级联动的选择

a. 允许用户增加内容

b. 允许用户选择查看某一个级别内容

dic = {
    "江西": {"萍乡": ["安源", "彭高", "上栗"], "新余": ["良山", "新钢", "兴安岭"], },
    "北京": {"大兴区": ["礼贤镇", "魏善庄镇", "北臧村镇"], "昌平区": ["沙河", "化庄", "白浮泉"], },
    "福建": {"莆田": ["荔城", "西天尾", "九化山"], "厦门": ["湖里", "思明", "海仓"], }}
print("目前可查询的省份：江西、北京、福建")
province = input("请输入省份或者输入N新建： ")
if province == "N":
    new_province = input("请输入省份：")
    new_city = input("请输入城市：")
    new_town = input("请输入城镇信息：")
    dic[new_province] = {new_city: [new_town]}


while province not in dic:
    print(dic)
    province = input("输入查询： ")


while province in dic:
    new_menu = dic[province]
    for k in new_menu:
        print(k, end="\n")
    choice_city = input("请输入城市：")
    if choice_city not in new_menu:
        print("错误城市输入，请从新输入： ")
        continue
    else:
        new_menu2 = new_menu.get(choice_city)
        for i in new_menu2:
            print(i, end="\n")
        choice_town = input("请输入城镇信息：")
        if choice_town in new_menu2:
            print(
                "信息输入正确，省份：{}，城市：{}，城镇：{}".format(
                    province,
                    choice_city,
                    choice_town))
        break

4.题
有两个列表
l1 = [11, 22, 33]
l2 = [22, 33, 44]

a. 获取内容相同的元素列表
b. 获取l1中有， l2中没有的元素列表
c. 获取l2 中有，l1中没有的元素列表
d. 获取l1 和 l2 中内容都不同的元素

l1 = [11, 22, 33]
l2 = [22, 33, 44]
list = []
for i in l1:
    for l in l2:
        if i==l:
            list.append(i)
print(list)

l1 = [11, 22, 33]
l2 = [22, 33, 44]
list = []
for i in l1:
    a = 0
    for j in l2:
        if i==j:
            a=1
    if a==0:
        list.append(i)
print(list)

l1 = [11, 22, 33]
l2 = [22, 33, 44]
list = []
for i in l2:
    a = 0
    for j in l1:
        if i==j:
            a=1
    if a==0:
        list.append(i)
print(list)

l1 = [11, 22, 33]
l2 = [22, 33, 44]
list = []
c = []
ab = l1+l2
for i in ab:
    if i in l1 and i in l2:
        c.append(i)
    else:
        list.append(i)
print(list)

5.题
a. 将字符串 s = "alex"转换为列表
b. 将字符串s = "alex"转换为元组
c. 将列表li = [“alex”, “seven”]转换为元组
d. 将元组 tu = (“Alex”, “seven”)转换为列表
a. 将字符串 s = "alex"转换为列表
s = "al1.题

#a. 将字符串 s = "alex"转换为列表
s = "alex"
li = list(s)
print(li)


#b. 将字符串s = "alex"转换为元组


s = "alex"
li = tuple(s)
print(li)


#c. 将列表li = ["alex", "seven"]转换为元组
li = ["alex", "seven"]
tu = tuple(li)
print(tu)


#d. 将元组 tu = ("Alex", "seven")转换为列表
tu = ("Alex", "seven")
li = list(tu)
print(li)