C语言作业:查看整数的任意位数

// Code file created by C Code Develop

#include "stdio.h"
#include "stdlib.h"

int main() {
    int innumber = 0;
    int inplace = 0;
    int outnumber = 0;
    int indlex = 0;
    int t = 0; 
    int n = 1;
    int m = 0;
    int save1 = 0;
    int save2 = 0;
    printf ("请输入你需要查看位数的数字\n");
    scanf ("%d", &innumber);
    printf ("你要查看第几位数？\n");
    scanf ("%d", &inplace);
    do{
        t++;
        n *= 10;
        m = (innumber % n)/(n/10);
        save1 += m;
        save1 *= 10;
        save2 += m * n / 10;
    }while(innumber != save2);
    //printf ("%d\n", save1);
    save1 /= 10;
    t = 0;
    n = 1;
    do{
        t++;
        n *= 10;
    }while(t < inplace);
    outnumber = (save1 % n)/(n/10);
    printf ("你所输入的数字是%d，它的第%d位数是%d\n",innumber ,inplace ,outnumber);
    
    //printf ("%d\n", save1 / 10);
    return 0;
}

仅供参考,请自行修改