三种获取当天剩余时间的简洁方式,分别使用DateUtils、DateTime和LocalDateTime,
public class TimeTest {
@Test
public void getTime() {
//方法一
long milliSecondsLeftToday = 86400000 - DateUtils.getFragmentInMilliseconds(Calendar.getInstance(), Calendar.DATE);
long secondsLeftToday = 86400 - DateUtils.getFragmentInSeconds(Calendar.getInstance(), Calendar.DATE);
System.out.println("当天剩余毫秒1:" + milliSecondsLeftToday);
System.out.println("当天剩余秒1:" + secondsLeftToday);
//方法二
DateTime dateTime = new DateTime().millisOfDay().withMaximumValue();
long millSeconds2 = new Duration(new DateTime(), dateTime).getMillis();
long count = new Duration(new DateTime(), dateTime).getStandardSeconds();
System.out.println("当天剩余毫秒2:" + millSeconds2);
System.out.println("当天剩余秒2:" + count);
//方法三:LocalDateTime和ChronoUnit为1.8新增
LocalDateTime midnight = LocalDateTime.now().plusDays(1).withHour(0).withMinute(0).withSecond(0).withNano(0);
long millSeconds = ChronoUnit.MILLIS.between(LocalDateTime.now(),midnight);
long seconds = ChronoUnit.SECONDS.between(LocalDateTime.now(), midnight);
System.out.println("当天剩余毫秒3:" + millSeconds);
System.out.println("当天剩余秒3:" + seconds);
}
}
//获取直到今天结束剩余的秒数
public static Long getTodayLeftSeconds(){
return 86400 - DateUtils.getFragmentInSeconds(Calendar.getInstance(), Calendar.DATE);
原文链接:https://blog.youkuaiyun.com/a_bang/article/details/53589206