python,求解_count + int(id[i]) * weight[i]-优快云博客

本文链接：https://blog.youkuaiyun.com/weixin_46625745/article/details/119966508

博客内容涉及一个身份证验证程序的Python脚本，作者遇到字符串索引越界的问题。在`for`循环中，当`i=1`时，程序尝试访问`weight`列表的元素导致错误。问题可能出在对输入身份证号的处理上。解决方案可能包括检查身份证号的长度和格式是否正确，以及遍历权重数组时确保不会超出字符串长度。

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照着网上做的身份证核验的小脚本

为什么在函数jia（）里当i=1，函数执行到for i in range(0,len(id)): count = count + int(id[i]) * weight[i] 就报string index out of range, 这里的weight[1]=9 啊，求指点一下吗？
源程序如下：
import tkinter as tk
from tkinter import *

def jia():
id = var.get() #610328 1955 0000 251(17)
if len(id) != 17 or id.isdigit() == False: #身份核验
L2["text"] = '输入错误'

i = 0
count = 0
weight = [7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2] #权重项
checkcode = {'0':'1','1':'1','2':'x','3':'9','4':'8','5':'7','6':'6','7':'5','8':'5','9':'3','10':'2'}
#print(len(id))
for i in range(0,len(id)): #len(id)=17

count = count + int(id[i]) * weight[i]
id = checkcode[str(count % 11)]

print("----------------------------")
if c == int(digit[18]):
L2['text'] = id
else:
L2['text'] = id

B2['state']= 'normal'

def clear():
L2['text'] = " "
var.set("")
B2['state'] = 'disabled'

w = Tk()
var = StringVar()
w.title('身份证验证程序')
w.geometry('900x500+100+100')

L1 = tk.Label(w,text = "请输入身份证号码",font = ("Arial",30))
T1 = tk.Entry(w,font=("黑体",30),textvariable = var)
B1 = Button(w,text = '输入完成',command = jia, font=("黑体",20))
B2 = Button(w,text = '清除数据',command = clear,font=("黑体",20),state = "disabled")
L2 = tk.Label(w,text = " ",font=("Arial",30))

B1.grid(row = 3, column = 20)
B2.grid(row = 4, column = 20)
L1.grid(row = 0, column = 45)
T1.grid(row = 1, column = 45)
L2.grid(row = 6, column = 45)
w.mainloop()