思路
这题要用贪心算法来做,具体贪心的地方就是我们先把所有的会议按照结束时间排序,然后我们只考虑当前时间能开的结束时间最早的会议,然后就可以计算出来最多的宣讲场次。
这里需要理解的是sort()的使用方法,详见之前的文章。
代码
import java.util.Arrays;
public class programmertest {
public static class Program {
public int start;
public int end;
public Program(int start, int end) {
this.start = start;
this.end = end;
}
}
public static int getAns(Program[] programs, int now) {
Arrays.sort(programs, (o1, o2) -> {
return o1.end - o2.end;
});
int ans = 0;
for (int i = 0; i < programs.length; i++) {
if (now <= programs[i].start) {
now = programs[i].end;
ans++;
}
}
return ans;
}
public static void main(String[] args) {
Program p1 = new Program(9,11);
Program p2 = new Program(6,8);
Program p3 = new Program(7,9);
Program p4 = new Program(8,10);
Program p5 = new Program(4,6);
Program[] p = new Program[]{p1,p2,p3,p4,p5};
int m = getAns(p,0);
System.out.println(m);
}
}