杭电OJ1062---Text Reverse(c++)(C++库getline的使用)

最新推荐文章于 2024-10-09 20:45:03 发布

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最新推荐文章于 2024-10-09 20:45:03 发布

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本文介绍了一个编程挑战，要求参赛者实现一个程序，该程序能够读取一行文本并将其所有单词逆序输出。示例代码使用C++实现，通过读取整数后的换行符和整行输入来正确处理每一行文本。

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Text Reverse

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 54493 Accepted Submission(s): 20797

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

Output

For each test case, you should output the text which is processed.

Sample Input

3 olleh !dlrow m'I morf .udh I ekil .mca

Sample Output

hello world! I'm from hdu. I like acm.

Hint

Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.

题解：

#include<cstdio>
#include<iostream>
#include<cmath>
#include<string>
using namespace std;
int main()
{
   int n;
   cin >> n;
   getchar();
   while (n--)
   {
       int k = 0;
       string str;
       getline(cin,str);
       for (int i = 0; i<str.length();i++)
       {
           if (str[i] == ' ')
           {
               for (int m = i - 1; m >= k; m--)
               {
                   cout << str[m];
               }
               cout << " ";
               k = i + 1;
           }
       }
           for (int m = str.length()- 1; m >=k; m--)
               cout << str[m];
           cout << endl;
   }
   return 0;
}