HDOJ 2057

A + B Again

Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output
For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output
0
2C
11
-2C
-90

Author
linle

Source
校庆杯Warm Up

解题思路
llX的使用

AC

#include<stdio.h>
using namespace std;
int main() {
	long long a, b,ans;
	while (scanf("%llX %llX", &a, &b) != EOF) {
		ans = a + b;
		if (ans < 0)
			printf("-%llX\n", -ans);
		else
			printf("%llX\n", ans);
	}
	return 0;
}