创建一个简单的spring项目

1.首先创建一个maven项目

2.向pom文件中导入需要的依赖

<dependencies>
        
        <!--spring依赖-->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-context</artifactId>
            <version>5.3.20</version>
        </dependency>
        <!--测试-->
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>4.12</version>
        </dependency>
 </dependencies>

3.编写service层

public class UserService {
    public void save(){
        System.out.println("UserService run......");
    }
}

4.resources文件下创建xml文件

 5.在xml文件中创建我们需要用到的对象

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="userService" class="com.springTest.service.UserService"/>

</beans>

6.进行测试

package com.springTest.dao;

import com.springTest.service.UserService;
import org.junit.Test;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class UserDao {

    @Test
    public void testSave(){
        //读取xml文件
        ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("application.xml");
        //获取创建好的对象
        UserService bean = context.getBean(UserService.class);
        //调用方法
        bean.save();
    }
}

7.测试结果