注意!优先级较高
#include<iostream>
using namespace std;
int mon_each[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};
int sum_year[2]={365,366};
int a,b,c,y1,y2;
bool isRyear(int year)
{
if(!(year%400)||(!(year%4) && year%100)) //!!!!!!!!!
{
return 1;
}
return 0;
}
int get(int year,int month,int day)//某年某月某日 是该年中的第几天
{
int sum=0;
int is_R;
is_R=isRyear(year);
for(int i=1;i<=month;i++)
{
if(i==month)
sum+=day;
else sum+=mon_each[is_R][i];
}
return sum;
}
int gett(int year1,int month1,int day1,int year2,int month2,int day2)//两个日期相差的天数
{
int sum_year1=get(year1,month1,day1);
int sum_year2=get(year2,month2,day2);
// cout<<"sum_year1:"<<sum_year1<<endl;
// cout<<"sum_year2"<<sum_year2<<endl;
int is_R;
int sum=0;
for(int i=year1;i<=year2;i++)
{
is_R=isRyear(i);
if(year1==year2) //注意year1==year2的情况
{
sum+=sum_year2-sum_year1;
}else{
if(i==year1)
{
sum+=(sum_year[is_R]-sum_year1);
}else if(i==year2)
{
sum+=(sum_year2);
}else{
sum+=sum_year[is_R];
}
}
}
// cout<<sum<<endl;
return (sum+2-1)%7+1;
}
int main()
{
// cout<<(60385+2-1)%7+1;
cin>>a>>b>>c>>y1>>y2;
int year,month,day;
month=a;
int is_R;
int aa,bb;
for(int i=y1;i<=y2;i++)
{
is_R=isRyear(i);
aa=gett(1850,1,1,i,month,1);//i年month月1日是星期几
bb=(b-1)*7+c;
if(c<aa) //!!模拟算一下,也可以循环天数,模拟
{
day=bb+7-aa+1;
}else{
day=bb-aa+1;
}
if(day<=mon_each[is_R][a])
{
printf("%4d/%02d/%02d\n",i,month,day);
}else {
printf("none\n");
}
}
return 0;
}