java 获取静态目录文件

朕的爱妃呢

已于 2024-01-12 09:03:30 修改

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分类专栏： JAVA 文章标签： java 开发语言

于 2023-11-11 09:25:02 首次发布

本文链接：https://blog.youkuaiyun.com/weixin_45229007/article/details/134344519

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		String path = "excel/poverty.xlsx";
		//jar包可以获取 已测试
        InputStream template = Thread.currentThread().getContextClassLoader().getResourceAsStream(path);
        System.out.printf("THREAD:");
        System.out.println(template);

		//jar包可以获取 已测试
        ClassPathResource classPathResource = new ClassPathResource(path);
        InputStream inputStream = classPathResource.getInputStream();
        System.out.printf("ClassPathResource:");
        System.out.println(inputStream);
        System.out.println(classPathResource.getPath());
        System.out.println(classPathResource.getFilename());

		//jar包可以获取 已测试
        URL resource = Thread.currentThread().getContextClassLoader().getResource(path);
        System.out.printf("URL.GETPATH:");
        System.out.println(resource.getPath());
        System.out.println(resource.openStream());