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最新推荐文章于 2024-01-29 17:33:42 发布

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分类专栏：蓝桥杯试题集：基础

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本文提供了一个C++程序，用于将20以内的整数转换为其英文表述形式。通过使用预定义的字符串数组，该程序能够处理个位数和十位数的转换，包括特殊规则的应用，如'twenty'和'thirty'等。输入两个整数，程序将分别显示它们的英文表述，如果第二个数字为零，则会输出'o'clock'。

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代码

#include <cstring>
#include <iostream>
#include <vector>
#include <algorithm>
#include <math.h>
using namespace std;
string b[]={"twenty","thirty","forty","fifty"};
string a[21]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty"};
int main(){
    int n,m;
    cin >> n >> m; 
    if(m){
        if(n<=20){
            cout << a[n] << " ";
        }
        else{
            cout << b[n/10-2] << " " << a[n%10] << " ";
        }
        if(m<=20){
            cout << a[m] << " ";
        }
        else{
            cout << b[m/10-2] << " " << a[m%10];
        }
    }else{
        if(n<=20){
            cout << a[n] << " ";
        }
        else{
            cout << b[n/10-2] << " " << a[n%10] << " ";
        }
        cout << "o'clock";
    }
}