在Java中HashSet是用HashMap实现的,在jad8以前HashMap是用数组+链表实现的,在jdk8中变成了数组+链表+红黑树。下面介绍jdk8中HashMap的实现原理。
数组扩容
几个概念:
数组容量:数组的长度,初始值默认为16;
负载因子:作为数组扩容的判断条件,默认为0.75;
临界值:数组容量*负载因子;
1,在new HashMap()的时候不会创建数组,而是在第一次调用put()方法的时候创建数组。
2,当数组中元素的个数超过临界值时就会进行数组扩容,大小变成原来的两倍。
3,当某个链表的长度大于8且数组容量大于64的时候链表就会转为红黑树。
添加元素
当调用put(key,value)方法时,首先计算key的hashCode,然后用散列函数计算出该值在数组中对应的位置,下面分情况讨论:
1,该位置没有元素,直接放入;
2,该位置有元素,且该链表的哈希值和key的哈希值不同,直接放入到链表的末尾。
3,该位置有元素,且在链表中存在与key的哈希值相同的元素。会调用key的equals()方法,如果返回false,添加成功,如果返回true会用value覆盖掉原来的值。
一道例题
import java.util.HashSet;
public class Map {
public static void main(String[] args) {
HashSet<Person> people = new HashSet<>();
Person p2 = new Person("xing", 33);
Person p1 = new Person("zhangxueyou", 55);
people.add(p1);
people.add(p2);
System.out.println("people = " + people);
p2.setAge(18);
System.out.println("people = " + people);
//p2年龄改变HashCode也改变,但people里面的xing的HashCode还是年龄为33时的HashCode
//执行remove时没有相同的HashCode,删除失败
people.remove(p2);
System.out.println("people = " + people);
//添加年龄为18的xing, HashCode不同,添加成功
people.add(new Person("xing", 18));
System.out.println("people = " + people);
//添加年龄为33的xing,虽然哈希值相同但使用equal方法比较时不同,仍然可以添加成功
people.add(new Person("xing",33));
System.out.println("people = " + people);
}
}
class Person implements Comparable<Person>{
String name;
int age;
@Override
public String toString() {
return "Person{" +
"name='" + name + '\'' +
", age=" + age +
'}';
}
@Override
public boolean equals(Object o) {
if (this == o)
return true;
if (o == null || getClass() != o.getClass())
return false;
Person person = (Person) o;
if (age != person.age)
return false;
return name != null ? name.equals(person.name) : person.name == null;
}
@Override
public int hashCode() {
int result = name != null ? name.hashCode() : 0;
result = 31 * result + age;
return result;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Person(String name, int age) {
this.name = name;
this.age = age;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public int compareTo(Person o) {
return this.name.compareTo(o.name);
}
}
输出结果:
people = [Person{name='zhangxueyou', age=55}, Person{name='xing', age=33}]
people = [Person{name='zhangxueyou', age=55}, Person{name='xing', age=18}]
people = [Person{name='zhangxueyou', age=55}, Person{name='xing', age=18}]
people = [Person{name='zhangxueyou', age=55}, Person{name='xing', age=18}, Person{name='xing', age=18}]
people = [Person{name='zhangxueyou', age=55}, Person{name='xing', age=18}, Person{name='xing', age=18}, Person{name='xing', age=33}]