#include<stdio.h>
int main(){
char arr1[26] = {0};//假设只有26个字母a~z
char arr2[20] = {0};//假设输入的字符串长度小于20
int len1 = sizeof(arr1)/sizeof(arr1[0])-1;
int len2 = sizeof(arr2)/sizeof(arr2[0])-1;
scanf("%s",arr2);
printf("输入字符串是%s\n",arr2);
int num;
for(int i = 0;i <= len2;i++){
num = arr2[i] - 'a';//对a进行相减得到数组1的角标
arr1[num]++;//将对应角标的值加一
}
for(int j = 0;j <= len1;j++){
printf("%c的次数是%d\n",j+97,arr1[j]);
}
}
结果如下: