第一行输出一个第二行输出两个以此类推
方法一:用while
a='abcd1234567890r'
hang=1
count=0
i=0
while i<len(a):
print(a[i],end='')
count+=1
if count==hang:
print()
count=0
hang+=1
i+=1

方法二:用for
a='1234567891011121314151617181'
hang=1
count=0
for i in a:
print(i,end="")
count+=1
if count==hang:
print()
count=0
hang+=1
