836. 矩形重叠
难度:Low
掌握程度:Low
rec1右 <= rec2左
rec1左>= rec2右
rec1下 >= rec2上
rec1 上<= rec2下
var isRectangleOverlap = function(rec1, rec2) {
if(rec1[2] <= rec2[0] || rec1[0] >= rec2[2] || rec1[1] >= rec2[3] || rec1[3] <= rec2[1]){
return false;
}else{
return true;
}
};