Offer 18. 删除链表的节点

Offer 18. 删除链表的节点

1. python

class Solution:
    def deleteNode(self, head: ListNode, val: int) -> ListNode:
        pre,cur = head,head.next
        if val == pre.val:
            return head.next
        while cur and cur.val != val:
            pre = cur
            cur = cur.next
        if cur:
            pre.next=cur.next
        return head

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