Leetcode-柠檬水找零

这道题深刻的诠释了什么才叫简单题！！！！！！！
之前做的那些叫什么简单题啊！！！！！！

class Solution:
    def lemonadeChange(self, bills: List[int]) -> bool:
        if(bills[0]!=5):
            return False
        else:
            five = 1
        ten = 0
        twenty = 0
        for i in range(1,len(bills)):
            if(bills[i]==10 and five>=1):
                five -= 1
                ten += 1
            elif(bills[i]==20 and five>=1 and ten>=1):
                five-=1
                ten-=1
            elif(bills[i]==20 and five>=3):
                five-=3
            elif(bills[i]==5):
                five+=1
            else:
                return False
        return True

做完看了评论区，这题真没啥技巧，大家想法都一样，希望复试就考这种题谢谢