【剑指offer】替换空格
题目
请实现一个函数,将一个字符串中的空格替换成“%20”。例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy.
解法一:
package offer;
public class Offer_2 {
public static String replaceSpace(StringBuffer str) {
String str1 = str.toString();
String str2 = str1.replace(" ", "%");
return str2;
}
public static void main(String[] args) {
System.out.println(replaceSpace(new StringBuffer("We Are Happy.")));
}
}
解法二:
package offer;
public class Solution {
public static String replaceSpace(StringBuffer str) {
String str1=str.toString();
char[] charArray = str1.toCharArray();
StringBuilder sBuilder = new StringBuilder();
for (char c : charArray) {
if(c==' ') {
sBuilder.append("%20");
}else {
sBuilder.append(c);
}
}
String string = sBuilder.toString();
return string;
}
public static void main(String[] args) {
System.out.println(replaceSpace(new StringBuffer("We Are Happy.")));
}
}
在完成这个代码的过程中,我遇到了String和StringBuffer傻傻分不清楚的情况,做了相应总结,详细见:
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