A + B Problem Too HDU - 2101

最新推荐文章于 2020-02-11 21:47:40 发布

李不离钟^

最新推荐文章于 2020-02-11 21:47:40 发布

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本文链接：https://blog.youkuaiyun.com/weixin_43981207/article/details/84889260

本文探讨了一种特殊的A+B问题，重点在于判断A与B之和是否能被86整除。通过给出示例输入与输出，详细解析了C++代码实现，包括读取两个整数并进行条件判断，最终输出yes或no。

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This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes

因为不懂怎么样输入多组数据，所以只能假设输入两组；

#include "pch.h"
#include <iostream>
using namespace std;
int main()
{
	int A[2], B[2];
	cin >> A[0] >> B[0] >> A[1] >> B[1];
	if ((A[0] + B[0]) % 86 == 0)
	{
		cout << "yes";
	}
	else
	{
		cout << "no"<<'\n';
	}
	if ((A[1] + B[1]) % 86 == 0)
	{
		cout << "yes";
	}
	else
	{
		cout << "no"<<'\n';
	}
}