easyui[2]
用户的权限可以是一对多,也可以是多对多
一对多的弊端就是:一个菜单不能对应多个用户!
具体的思路的话就是以下这样子:
1.执行数据库脚本
2.修改原有的实体类
3.建立实体类
4.创建dao
5.修改原有的dao
6.新增web的方法
7.新增登入界面,跳入前端树形菜单
关于权限这一块在我的上一篇博客中有初步的了解:
接下来我们就开始写代码啦:
用户的dao方法:
package com.wt.dao;
import java.sql.SQLException;
import java.util.List;
import java.util.Map;
import com.wt.util.JsonBaseDao;
import com.wt.util.JsonUtils;
import com.wt.util.PageBean;
import com.wt.util.StringUtils;
public class UserDao extends JsonBaseDao {
/**
* 登录查询用户表 登录
* @return
* @throws SQLException
* @throws IllegalAccessException
* @throws InstantiationException
*/
public List<Map<String, Object>> list(Map<String, String[]> paMap,PageBean pb) throws InstantiationException, IllegalAccessException, SQLException{
String sql = "select * from t_easyui_user_version2 where true ";
String uid = JsonUtils.getParamVal(paMap, "uid");
String upwd = JsonUtils.getParamVal(paMap, "upwd");
if(StringUtils.isNotBlank(uid)) {
sql = sql+" and uid = "+uid;
}
if(StringUtils.isNotBlank(upwd)) {
sql= sql+" and upwd = "+upwd;
}
return super.executeQuery(sql, pb);
}
/**
* 通过中间表查询登录用户所对应的权限
* @param paMap
* @param pb
* @return
* @throws InstantiationException
* @throws IllegalAccessException
* @throws SQLException
*/
public List<Map<String, Object>> listMenu(String uid,PageBean pb) throws InstantiationException, IllegalAccessException, SQLException{
String sql = "select * from t_easyui_usermenu where true ";
if(StringUtils.isNotBlank(uid)) {
sql= sql+" and uid = "+uid;
}
return super.executeQuery(sql, pb);
}
}
在menudao中改变了一个小地方:
public List<Map<String, Object>> listMenuSef(Map<String, String[]> map,PageBean pb) throws InstantiationException, IllegalAccessException, SQLException{
String sql="select * from t_easyui_menu where true";
String id=JsonUtils.getParamVal(map, "menuHid");
if(StringUtils.isNotBlank(id)) {
sql=sql+" and menuid in ("+id+") ";
}
else {
sql=sql+" and menuid = -1";
}
return super.executeQuery(sql, pb);
}
在子控制器中
package com.wt.web;
import java.sql.SQLException;
import java.util.List;
import java.util.Map;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.wt.dao.UserDao;
import com.zking.framework.ActionSupport;
public class UserAction extends ActionSupport {
private UserDao ud=new UserDao();
public String login(HttpServletRequest req,HttpServletResponse resp) throws InstantiationException, IllegalAccessException, SQLException {
List<Map<String, Object>> list = this.ud.list(req.getParameterMap(), null);
if(list!=null&&list.size()>0) {
List<Map<String, Object>> listMenu = this.ud.listMenu(req.getParameter("uid"), null);
StringBuilder sb=new StringBuilder();
for (Map<String, Object> map : listMenu) {
sb.append(","+map.get("menuId"));
}
//,001,002,.....
req.setAttribute("menuHid", sb.substring(1));
}
else {
return "login";
}
return "index";
}
}
jsp界面的
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<form action="${pageContext.request.contextPath}/userAction.action?methodName=login" method="post">
uid:<input type="text" name="uid"><br>
upwd:<input type="text" name="upwd"><br>
<input type="submit">
</form>
</body>
</html>
index界面的话在上一篇博客有写:
结果如下: