链表
1.删除带头结点的单链表中所有值为x的结点并释放空间
class ListNode{
int val ;
ListNode next;
public ListNode(int x) {
val = x;
}
public ListNode(int[] arr) {
if(arr == null || arr.length == 0) {
throw new IllegalArgumentException("ARR CAN NOT BE EMPTY");
}
val = arr[0];
ListNode cur = this;
for(int i = 1 ; i < arr.length ; i ++) {
cur.next = new ListNode(arr[i]);
cur = cur.next;
}
}
public String toString() {
StringBuilder res = new StringBuilder();
ListNode cur = this;
while(cur != null) {
res.append(cur.val + "->");
cur = cur.next;
}
res.append("NULL");
return res.toString();
}
}
public class removeListNode {
public static void main(String[] args) {
int[] nums = {1,2,4,3,6,4,2};
ListNode head = new ListNode(nums);
System.out.println(head);
ListNode node = removeElement(head, 1);
System.out.println(node);
}
public static ListNode removeElement(ListNode head, int val) {
while(head != null && head.val == val) {
head = head.next;
}
if(head == null) {
return head;
}
ListNode prev = head;
while(prev.next != null) {
if(prev.next.val == val) {
prev.next = prev.next.next;
}else {
prev = prev.next;
}
}
return head;
}
}