Mysql基础部分(18)---视图

最新推荐文章于 2025-05-12 13:57:25 发布

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最新推荐文章于 2025-05-12 13:57:25 发布

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分类专栏： MySQL基础文章标签： mysql sql 数据库

本文链接：https://blog.youkuaiyun.com/weixin_43900321/article/details/106156942

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本文深入探讨Mysql视图的概念、创建与修改方法，通过多个案例解析视图的使用技巧，包括视图更新的限制条件及如何进行视图的查询与管理。

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#视图
/*
含义：虚拟表，和普通表一样使用
mysql5.1版本出现的新特性，是通过表动态生成的数据

比如：舞蹈班和普通班的对比

	创建语法的关键字	s是否实际占用物理空间	使用
视图	create view		只是保存了sql逻辑	增删改查，只是一般不能增删改
表	create table		保存了数据		增删改查
*/

#案例：查询姓张的学生名和专业名
SELECT stuname,majorname
FROM stuinfo s
INNER JOIN major m ON s.`majorid` = m.`id`
WHERE s.`stuname` LIKE '%张%';

CREATE VIEW v1
AS 
SELECT stuname,majorname
FROM stuinfo s
INNER JOIN major m ON s.`majorid` = m.`id`;

SELECT * FROM v1
WHERE stuname LIKE '张%';

#一、创建视图
/*
语法：
create view 视图名
as
查询语句;
*/
USE myemployees;

#1.查询姓名中包含a字符的员工名，部门名和工种信息
#①创建
CREATE VIEW myv1
AS

SELECT last_name,department_name,job_title
FROM employees e
JOIN departments d ON e.department_id = d.department_id
JOIN jobs j ON j.job_id = e.job_id;
 
#②使用
SELECT * FROM myv1 WHERE last_name LIKE '%a%';

#2.查询每个部门的平均工资级别
#创建视图查看每个部门的平均工资
CREATE VIEW myv2
AS 
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id;

SELECT myv2.`ag`,g.grade_level
FROM myv2
JOIN job_grades g
ON myv2.`ag` BETWEEN g.`lowest_sal` AND g.`highest_sal`;

#3.查询平均工资最低的部门信息
SELECT * FROM myv2 ORDER BY ag LIMIT 1;

#4.查询平均工资最低的部门名和工资
CREATE VIEW myv3
AS 
SELECT * FROM myv2 ORDER BY ag LIMIT 1;

SELECT d.*,m.ag
FROM myv3 m
JOIN departments d
ON m.`department_id`=d.`department_id`;


#二、视图的修改
#方式一：
/*
create or replace view 视图名
as
查询语句;
*/

SELECT * FROM myv3;

CREATE OR REPLACE VIEW myv3
AS 
SELECT AVG(salary),job_id
FROM employees
GROUP BY job_id;

#方式二：
/*
语法：
alter view 视图名
as
查询语句;
*/
ALTER VIEW myv3
AS 
SELECT * FROM employees;

#方式三：
/*
语法：drop view 视图名,视图名,...;
*/
DROP VIEW emp_v1,emp_v2,myv3;

#四、查看视图
DESC myv3;

SHOW CREATE VIEW myv3;

#五、视图的更新
CREATE OR REPLACE VIEW myv1
AS 
SELECT last_name,email,salary*12*(1+IFNULL(commission_pct,0)) 'annual salary'
FROM employees;

CREATE OR REPLACE VIEW myv1
AS 
SELECT last_name,email
FROM employees;

SELECT * FROM myv1;
SELECT * FROM employees;
#1.插入
INSERT INTO myv1 VALUES('张飞','zf@qq.com');

#2.修改
UPDATE myv1 SET last_name = '张无忌' 
WHERE last_name='张飞';

#3.删除
DELETE FROM myv1 WHERE last_name='张无忌';

#具备以下特点的视图不允许更新
#①包含以下关键字的sql语句：分组函数,distinct,group by,having,union或union all
CREATE OR REPLACE VIEW myv1
AS
SELECT MAX(salary) m,department_id
FROM employees
GROUP BY department_id;

SELECT * FROM myv1;

#更新
UPDATE myv1 SET m=9000 WHERE department_id=10;

#②常量视图
CREATE OR REPLACE VIEW myv2
AS 
SELECT 'john' NAME;

SELECT * FROM myv2;

#更新
UPDATE myv2 SET NAME='lucy';

#③select 中包含子查询
CREATE OR REPLACE VIEW myv3
AS
SELECT department_id,(SELECT MAX(salary) FROM employees) 最高工资
FROM departments;

SELECT * FROM myv3;
#更新
UPDATE myv3 SET 最高工资=100000;

#④join
CREATE OR REPLACE VIEW myv4
AS
SELECT last_name,department_name
FROM employees e
JOIN departments d
ON e.department_id = d.department_id;

#更新
SELECT * FROM myv4;
UPDATE myv4 SET last_name='张飞' WHERE last_name='Whalen';
INSERT INTO myv4 VALUES('陈真','xxx');

#⑤from一个不能更新的视图
CREATE OR REPLACE VIEW myv5
AS
SELECT * FROM myv3;

#更新
SELECT * FROM myv5;
UPDATE myv5 SET 最高工资=10000 WHERE department_id=60;


#⑥where字句的子查询引用了from字句中的表
CREATE OR REPLACE VIEW myv6
AS
SELECT last_name,email,salary
FROM employees
WHERE employee_id IN(
	SELECT manager_id
	FROM employees
	WHERE manager_id IS NOT NULL
);
#更新
SELECT * FROM myv6;
UPDATE myv6 SET salary=10000 WHERE last_name='K_ing';