18打卡 二叉树02

层序遍历

迭代思路

代码实现


    public List<List<Integer>> levelOrder(TreeNode root) {
        List<List<Integer>> res = new ArrayList<>();
        if (root == null) return res;
        Queue<TreeNode> queue = new ArrayDeque<>();
        queue.offer(root);
        while (!queue.isEmpty()) {
            //解决“出几个”的问题
            int size = queue.size();
            ArrayList<Integer> path = new ArrayList<>();
            while (size-- > 0) {

                TreeNode poll = queue.poll();
                path.add(poll.val);

                if (poll.left != null) queue.offer(poll.left);
                if (poll.right != null) queue.offer(poll.right);
            }
            res.add(path);
        }
        return res;
    }

翻转二叉树

 //使用递归
    public TreeNode invertTree(TreeNode root) {
        helper(root);
        return root;

    }

    //确定递归函数的参数和返回值
    public void helper(TreeNode root) {

        //确定终止条件
        if (root == null) return;

        //确定单层循环的逻辑(函数自调用)
        swap(root);
        helper(root.left);
        helper(root.right);

    }

    private void swap(TreeNode root) {
        TreeNode temp = root.left;
        root.left = root.right;
        root.right = temp;


    }

*L0101. 对称二叉树

    private boolean compare(TreeNode left, TreeNode right) {

        if (left == null && right != null) {
            return false;
        }
        if (left != null && right == null) {
            return false;
        }

        if (left == null && right == null) {
            return true;
        }
        if (left.val != right.val) {
            return false;
        }
        // 比较外侧
        boolean compareOutside = compare(left.left, right.right);
        // 比较内侧
        boolean compareInside = compare(left.right, right.left);
        return compareOutside && compareInside;
    }

二叉树的层序遍历可以通过不同的方法实现。其中一种方法是使用队列的思想。每次循环遍历一层的节点,将其子节点加入队列,并将遍历的值加入结果中。以下是一个用Python实现的例子: ```python # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution(object): def levelOrder(self, root): """ :type root: TreeNode :rtype: List[List[int]] """ <span class="em">1</span><span class="em">2</span><span class="em">3</span> #### 引用[.reference_title] - *1* [二叉树的层序遍历(Python语言)](https://blog.youkuaiyun.com/attitude36/article/details/110144216)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}}] [.reference_item style="max-width: 33.333333333333336%"] - *2* [python数据结构之树(2)—— 二叉树遍历|优快云创作打卡](https://blog.youkuaiyun.com/weixin_55073640/article/details/122758286)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}}] [.reference_item style="max-width: 33.333333333333336%"] - *3* [二叉树的层序遍历Python解法](https://blog.youkuaiyun.com/qq_43593534/article/details/123800081)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}}] [.reference_item style="max-width: 33.333333333333336%"] [ .reference_list ]
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